How do I factor [9r]2 +12r+4

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dude this is really hard ask ur teacher or someone

I guess you mean this 9r^2 + 12 r +4Because if you mean (9r) in 2 exponent, we'd get 81r^2 +12 r +4 which cannot be factored, because we would get a*c>b^2 and this gives conjugate solutions.(if you get what i mean).So 9r^2 + 12r +4 = 0 we see that a=9 b=12 and c=4We have to use the Quadratic Formula to find r1 and r2r1,2 = [ -b±√(b^2 - 4ac) ] /2ar1,2 = [-12±√(12^2 - 4*9*4] /2*9r1,2 = [-12±√(144-144] /18r1,2 = [-12±√(0) ] /18r1 = (-12 + 0) /18              r2=(-12 -0) / 18r1=-12 / 18=-2/3               r2=-12 /18 = -2/3Those solutions we put on this formula (x-r1)*(x-r2)we have now [x-(-2/3)] * [x-(-2/3)][x+(2/3)] * [x+(2/3)]or(3x+2)*(3x+2)(3x+2)^2