How do you do this problem? Identify the focus and directrix of the parabola? the problem is xsquare=4y

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If x^2 = 4y, then y = (1/4)x^2The vertex occurs at (0,0) and the parabola is vertically oriented and opens up.The focus is a point that is the same distance from the parabola compared to the distance from the directrix to the parabola for every point on the parabola.The distance from the vertex to the directrix and the focus is 4 times the coefficient of the x^2 term of the parabola.In this case, that distance is 1 unit.The focus is at (0,1) and the directrix is the horizontal line located at y = -1