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A man has invested part of 25000 at 11% and the remainder at 6% His income in one year from these investments was the same as if he had invested the whole sum at 9% How much did he invest at each rate

jerry094

by jerry094 at April 03, 2010

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x = part at 11% 25000-x = part at 6% .11(x) + .06(25000-x) = .09(25000) .11x + 1500 - .06x = 2250 .05x = 750 x = 15,000 so, $15000 at 11% and $10000 at 6%

Jiyoungy Jiyoungy April 03, 2010

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