y=-x2+4x-1

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I don't know what your question is, so I'll make one up.Where is the vertex of this quadratic equation?y = -x^2 + 4x - 1Factor out a negative 1y = -1(x^2 - 4x + 1)Complete the squarey = -1(x^2 - 4x + 4 - 4 + 1)y = -1((x^2 - 4x + 4) - 4 + 1)y = -1((x - 2)^2 - 3)Distributey = -1(x - 2)^2 + 3The vertex of the parabola is at (2,3)