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how would you change log8 35 to a base 7?
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jimmerbob

by jimmerbob at March 25, 2010

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log8 (35) is a number...let's call it x.x = log8 (35)8^x = 8^[log8 (35)]8^x = 35log7 (8^x) = log7 (35)(x)(log7 (8)) = log7 (35)x = [log7 (35)] / [log7(8)]I hope that helps!
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McMayer McMayer March 25, 2010

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Use the change of base formula. log_b (x) = log_d(x)/log_d(b), where d = the base we want, b = the given base 8 and x = 35 log_8(35) = log_7(35)/log_7(8) Mathland
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mathguy mathguy March 26, 2010

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