Hi I do not understand how to solve this equation. Then it asks me to write a general solution to the equation.The equation states solve this equation 2 tan x +√12 =0 for x, where 0<x<2pi .

⚑ Flag

first change √12 to 2√3 2tanx = -2√3 tanx = -√3 tanx = -√3 at 2π/3 and 5π/3 So x = 2π/3 and 5π/3 The general solution is asking for all possible values of x. (Since tangent is periodic)This is found by adding multiples of π to your original answer for x x = 2π/3 + nπ