The center is (1, -2) from the numerators of standard form.
The denominator of the first term is a^2 so a = 4.
To find the vertices, add and subtract "a" to the coordinate of the center that is listed in the positive fraction- in this case , add and subtract 4 to the y coordinate. The vertices are (1, -6) and (1, 2)
Since this hyperbola is vertical the domain is all reals.
The range is (-∞, -6] unioned with [2, ∞)