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I'm in algebra 2, and we're currently learning circles. If you are given center is 7,5) and contains (3,-2), how do you derive an equation from that given info?

Teresa076

by Teresa076 at March 10, 2010

sorry for the previous typo

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well, i would find the distance between the center and the point so this distance would be a radius. Now just plug the necessary values ( radius, x and y of center) into the circle formula. sorry, im too lazy to go look up the circle formula right now...

carrotnosedude carrotnosedude March 10, 2010

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The equation of a circle is (x - h)^2 + (y - k)^2 = r^2 . (x, y) is a point on the circle, in this case (7, 5) (h, k) is the center, in this case (3, -2) Plug in the points you know and solve for r (3-7)^2 + (-2-5)^2 = r^2 16 + 49 = r^2 r^2 = 65 Put (h, k) and r^2 back in the equation. (x-7)^2 + (y-5) = 65 (people that are too lazy to give you good help shouldn't answer at all)

Nancy095 Nancy095 March 10, 2010

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