Help please- If log sub2 x=7, evaluate log sub2 16x^2

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2^7 = 128 so x = 128..that takes care of the 1st part. Now the second part can be broken down in the sum of logs:  log sub2 (16) + 2*log sub2 (x) = 4 + 2*log sub2 (128) =  4 + 14 = 18