Please help math 30 pure question on geometric sequences. Determine 2 geometric sequences whose first 3 terms are 18x-9, 2x+8, and x-1?

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The ratio between any two terms is always the same. (x-1)÷(2x+8) = (2x+8)÷(18x-9) Cross multiply (x-1)(a8x-9)=(2x+8)(2x+8) Simplify: 14x^2 - 59x - 55 = 0 Factor and solve:  (x-5)(14x + 11)    x = 5, x = -11/14 Fill in x = 5 to get 18(5) - 9, 2(5) + 8, 5 - 1 81, 18, 4, . . .   Sequence is formed by multiplying previous term by 2/9 Fill in -11/14 to get 18×(-11/14)-9, 2×(-11/14)+8, (-11/4)-1 -162/7, 45/7, -25/14  The common ratio is -5/18