how will u graph  f(x)=x²-8x-3? 

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A standard quadratic equation is y = ax^2 + bx + c.Since we have a quadratic equation, we know that the graph will open upwards or downwards. The easy way to figure out which way it opens is to see if a is either positive or negative. If a is positive, the graph will open upwards and have a minimum value. If a is negative, the graph will open downwards and have a maximum value.Now let's find the most important point- the vertex. The vertex is found by using this formula:(-b)  , f (-b) (2a)      (2a)(the y value is found by plugging in the x of your vertex into the original equation)I'm running out of space, so the vertex equals (4, -19). =)Okay, so now we just need points. The easiest way is to get 4 - 6 more points by just adding / subtracting by increments of 1 in your x then substituting x to find y. Then when you have your points, graph the equation.Of course, you could always use a graphing calculator, but you may not have that luxury on your test. ;)~ Azaler