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Use implicit differentiation to obtain dy/dx in terms of x and y for x2 - x2y + xy2 + y2 = 1

Stacy068

by Stacy068 at February 24, 2010

numbers are exponents for example x2 is x squared.

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Stacy - For simplicity, let dy/dx = y'.  So taking implicit differentiation of your problem is: 2x -2xy -x2y' +y2 = x(2y)y' + 2yy' = 0 Solve for y' to get your answer in terms of x and y. Hint: Any term where you have both x and y, always use the "product rule" of differentiation. Good Luck

Steve204 Steve204 February 24, 2010

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