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3e^(x+6)=12

Wendy961

by Wendy961 at February 22, 2010

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e^(x+6) = 4 x+6=4    <take the ln of both side and you get lne^(x+6). since lne = 1 and you can bring the exponent to the front of the equation, it'll look like this. (x+6)(1)=4 x=-2

yvettekimmy yvettekimmy February 22, 2010

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Divide by 3. e^(x+6) = 4.From here on, its the properties of logarithms. Remember, ln is equal to log base e.Take ln of both sides. ln(e^(x+6)) = ln4. One property of log is that you can take out an exponent and put it outside the log.So, we get (x+6)lne = ln4. ln(e) = 1 because you see it as log base e of e. e^n = e. e is equal to e^1. So, its 1.x + 6 = ln(4). x = ln(4) - 6

Raluchu Raluchu February 22, 2010

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