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find the standard form of the equation of the line that passes through the points (-7,1) and (-1,8)

234234243002

by 234234243002 at February 17, 2010

same kid i have no clue

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Ok, first lets find the slope of the line.  To find the slop, you take the change in the y values divided by the change in the x values.(-7-(-1))/(1-8) = 6/7Next, lets set up an equation in slope intercept form, because we have the slope and a point, but not the y-intercept. Slope intercept form looks like this:y = mx + bWhere m is the slope, and b is the y-intercept.  Simply substitute the y and x values in for a single point.-7 = (6/7)*1 + b-55/7 = bNext, we'll set up the same equation, only we'll simplify it in to standard form.y = (6/7)x - (55/7)(-6/7)x + y + (55/7) = 0

Hillm Hillm February 17, 2010

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