Find three consecutive intergers such that the sum of the first and twice the second is 17 more than twice the thrid.

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Let x = first consecutive integer Let x + 1 = second consecutive integer Let x + 2 = third consecutive integer x + twice(x + 1) = twice(x + 2) + 17 x + 2(x + 1) = 2(x + 2) + 17 x + 2x + 2 = 2x + 4 + 17 3x + 2 = 2x + 21 3x - 2x = -2 + 21 x = 19....This is the first consecutive integer. The second consecutive integer is 19 + 1 or 20. The third consecutive integer is 19 + 2 or 21. Here are the three consecutive integers: 19, 20, 21