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How do you do a 3 variable linear problem in the easiest manner?

scott201

by scott201 at February 16, 2010

A Company has excess manufacturing capacity and is considering devoting its excess capacity to products 1,2,and 3.

The production process uses three types of machines and the available capacity on the machines is as follows:
Milling Machine:  550Hrs/Week
Lathe:                  350Hrs./Week
Grinder:                150Hrs/Week
Profits and machine reqt. in hour for three products are as follows:
Catagory   Product 1   Product 2 Product 3
 Profit             50                 20          25
Milling Mach.   9                   3           5
Lathe               5                   4           0
Grinder           3                    0          2

Sales potentials for Product 1 and Product 2 exceeds max production and Product 3 is expected to sell no more than 20 units per week.
Formulate the LP problem

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amount of product 1 = x, amount of product 2 = y, amount of product 3 = z Milling  9x + 3y + 5z < or = 550 Lathe 5x + 4y + 0z < or = 350 Grinder 3x + 0y + 2z < or = 150 The "easiest" way to solve this is to use a graphing calculator that can do matrices- if that is what you are studying. Matrix A is a 3 x 3 matrix using the coefficients of the variables in your system. Matrix B is a 3 x 1 matrix using the answers (constraints) of your system. Calculate A inverse times B x = 38 8/9     y = 38 8/9    z = 16 2/3 Or use elimination Since you can't make fractional amounts round each answer up or down to create the greatest profit. The possibilities are x = 39, y = 39, z = 16 x = 39, y = 38, z = 17  (decrease the one with lowest profit) None of the possibilities that don't make all three products gives a maximum (you can check this) Profit on the first possibility is 50(39) + 20(39) + 25(16) = $3130 Profit on the second possibility is 50(39) + 20(38) + 25(17) = $3135  best answer

Nancy095 Nancy095 February 16, 2010

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