x+y+z=3x-2y+4z=53y+4z=5How you solve what x,y,and z = to

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x =  3 - y - z(3 - y - z) - 2y + 4z = 5-3y + 3z = 23y = 3z - 2(3z - 2) + 4z = 57z = 7z = 73y + 4(7) = 53y = -23y = -23/3x  - 23/3 + 7 = 3x = 11/3x = 11/3y = -23/3z = 7This is not the most efficient way to solve systems of equations, but it's what I know.  Simply solve each equation for a single variable, and then substitute that in to another equation.  You will learn other ways to do this, most likely in Pre-Calculus or Calculus.