Find the equation of the tangent line to the curve at :y= (x-1)/(x-2) at the point (3,2)

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take the first derivative to get y'(x)=-1/(x-2)^2then plug in the x value to get the slope so y'(3)=-1/(3-2)^2=-1now you know your slope is -1 and your point is (3,2)  plug that into point slope form(y-2)=-1(x-3) and your done