how would you simplify this problem?  [(1/2)^2-(1/4)^3]*2^3

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Using the standard order of operations, PEMDAS, perform the operations inside the brackets [ ] first. Once inside the brackets, do the exponents first to get [(1/4)-(1/64)]. Then do the subtraction. You'll need to get a common denominator for the fractions. This becomes [(16/64) - (1/64)], which equals [(15/64)]. Now you can go back to the original problem, which has become (15/64)*2^3. Again, do the exponent first to get (15/64)*8. Multiply to get 120/64, which reduces to 15/8, which can also be written as 1 7/8. I hope this helps!!