The first angle of a triangle is half the measure of the 2nd angle. The measure of the 3rd angle is 40 degrees more than 4 times the measure of the first. Find the measure of each angle

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so lets call the angles x, y and z, for angles 1, 2 and 3 respectively.x = (1/2) y z = 4x + 40 x + y + z = 180Use the first equation to substitute (1/2) y for all other occurrences of x:z = 2y + 40(3/2)y + z = 180Substitute 2y + 40 for z:(3/2)y + 2y + 40 = 1803.5y = 140     y = 40Then back substitute:z = 2*40 + 40 = 120x = (1/2) *40 = 20