what is the vertex and axis of symmetry of f(x)=x^2 +x +2?

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To find axis of symmetry, we use x = -b/2a From the given function, we know that a = 1, b = 1 and c = 2 x = -1/2(1) x = -1/2...This is your axis of symmetry for this parabola. To find the vertex, we plug x = -1/2 into the given function and simplify. f(-1/2) = (-1/2)^2 + (-1/2) + 2 f(-1/2) = 1/4 - 1/2 + 2 f(-1/2) = 7/4 Your vertex is the point (-1/2, 7/4). Did you folllow?