find the vertex and 3 points and graph f(x)=(x-3)square+2

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The equation of a parabola is y = a(x-h) + k  where ( h, k) is the vertex so the vertex in this case would be (3,2). Then you just make a table and plug in x values in the equation in order to get y values. When plugging in 2, and 4 into the original equation you get the points (2,3) and (4,3). Also you can graph the axis of symmetry which will always be the x value of the vertex so the axis of symmetry would be : x = 3 Here is a graph