How do I factor 64x^3-1 please? (factor it completely, that is)

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This is the difference of cubes.That is: 64x^3-1=(4x)^3-(1)^3                         =(4x-1)([4x]^2+(4x)(1) +[1]^2)                         =(4x-1)(16x^2+4x+1)Note: 16x^2+4x+1 is prime, that means it cannot be factored using real numbers