simplify x square -9/x+3

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Is your question to simplify (x^2 - 9)/(x+3) ?If so, just factor x^2 - 9, notice that it's a difference of squares: (x)^2 - (3)^2, which means x^2 - 9 = (x+3)(x - 3).  So your fraction is:(x^2 - 9)/(x+3) = [(x+3)(x-3)]/(x+3)  # (x+3)s cancel                         = (x-3)So it simplifies to x-3