Aris is twice as old as Rico while Jay is 24 years younger than Aris. If half of Aris age 6 years ago was 3 less than one-half the sum of Rico's age in 4 years and Jay's present age, find the ages?

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Start with writing equations of the information given to you, e.g. Aris is twice as old as Rico:A = 2*RJ = A - 24(1/2)(A - 6) = (1/2)*(R+4 + J) - 3Simplify that last one, it's a little hard to read:(1/2)A - 3 = (1/2)R + 2 + (1/2)J - 3 (1/2)A - (1/2)R - (1/2)J = 2   #multiply by twoA - R - J = 4So now our three equations are:A = 2R J = A - 24A - R - J = 4Substitute 2R for A, and A - 24 (or 2R -24) for J in the last equation.2R - R - 2R + 24 = 4-R = -20R = 20Back substitute:  A = 2R = 40J = A - 24 = 40 - 24 = 16So finally:Aris is 40 years oldRico is 20 years oldJay is 16 years old.