find two numbers such that twicce the first added to the second equals 19. and three times the first is 21 more thanthe second.

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First pick variables for the two numbers and convert the sentences to two equations."twice the first added to the second equals 19" is:2x + y = 19"three times the first is 21 more than the second it:3x = y + 21Next, I would rearrange the second equation slightly by subtracting y from both sides and then line up my two equations and add them together:2x + y = 193x - y = 21  (add equations to solve by elimination)5x = 40   (solve for x)x = 8Then plug your x value back in the first equation and solve for y:2(8) +y = 1916 + y = 19   (subtract 16 from both sides)y = 3So your solution is x = 8, y = 3, or (8, 3)