If Triangle ABC has vertices A=(0, 6), B = (-2, 3), and C=(2, 1). Find the coordinates of its vertices if it is translated by the equations: x'=x-4, y'=y-3. Need it all stepped out. Thanks!

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Just subtract 4 from each of the x coordinates and 3 from each of the y coordinates.So the coordinate of A' would be (0-4, 6-3) or A'=(-4, 3)Similarly the coordinate of B' would be (-2-4, 3-3) or B'=(-6, 0)And, finally, C' would be (2-4, 1-3) or C'=(-2, -2)Stepped out enough?