How would you solve x^2+5x-6=0. I'm getting confused because 6 is negative and 5 is positive.

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If you mean factor, that equation factors to (x+6)(x-1). If C, in the form X^2+Bx+C, is negative, then the signs of your factors are going to be opposite, like (x+  )(x-  ). If C is positive, then the sign of your factors are going to be the sign of B, in AX^2+BX+C. So, if you have (this is just random, may not be factorable) 3x^2-5x+3, you're going to have something like (x-  )(x-  )