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4x-12y=2;(10,-1)

jonh004

by jonh004 at November 24, 2009

write the equation of a line that is perpendicular to the given line and that passes through the given point.

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the slope is -1/3

saphiresong saphiresong November 24, 2009

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If you rewrite 4x - 12y = 2 in y = mx+b form, you get:12y = 4x - 2y = (1/3)x - 1/6so the slope of the line you're trying to find is the negative reciprocal of 1/3, which is -3.So now you know m, your line looks like:y = -3x +b,and you need to find b.  To find b, just plug in the point you're given, (10, -1) for x and y and then solve for b:-1 = -3*10 + b-1 = -30 + b29 = bSo your equation is y = -3x + 29

Alison037 Alison037 November 25, 2009

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