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What are the values of a , b and c in the following solution -4x^2 + 2x = 14 ?
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by Steven435 at April 28, 2012

solving radical equations

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ax^2 + bx + c = 0 so the value of a b c in the solution is -4x^2 + 2x = 14 -4x^2 + 2x - 14 = 0 a = -4 b = 2 c = -14

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Hapsari April 30, 2012

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Hapsari April 30, 2012

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ax^2+bx+c=0 so the value of a b c in the solution -4x^2+2x-14=0 is a=-4,b=2,c=-14

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psvishnu25 May 01, 2012