csc(x) / [cot(x) + tan(x)] = cos(x)Take the left hand side= csc(x) / [cot(x) + tan(x)]Convert to sines and cosines.= [1/sin(x)] / [(cos(x)/sin(x)) + (sin(x)/cos(x))]Now, multiply and divide by sin(x)cos(x).= (( sin(x)cos(x)) * [1/sin(x)]) / ((sin(x)cos(x)) * [(cos(x)/sin(x)) + (sin(x)/cos(x))])you will get= [cos(x)] / [cos^2(x) + sin^2(x)]Note that cos^2(x) + sin^2(x) =1, thereforeLHS = cos(x) / 1= cos(x) which is equal to RHS
Apply Today and receive complimentary 6 month Premium subscription!
