A four-person student advisory committee is to be randomly selected from five senior boys and six senior girls. What is the probability that the committee will be all senior boys?Please help!

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four people can be selected... _ _ _ _= the four positions there are <5> boys and <6> girls . in total there are 11 students to CHOOSE from..(so we're dealing with combination) If there are going to be all boys, we can just look at the 5 guys..and REMEMBER THAT as we choose, the number of boys to choose from decreases by 1 AND the total numbr of students to choose from decreases by 1..logic the possibility of the  first being a guy is (5/11) i.e 5 boys out of the 11 students wanting to be picked the possibility of the 2nd being a guy is (4/10) i.e 4 boys out of 10 students left the possibility of the 3rd advisory committtee being a guy is (3/9) i.e 3 out of the 9 left AND the possiblilty of the last pick being a guy AGAIN is (2/8) 2 guys out of the 8 students left Therefore the possibilty of having all the students in the committee as guys will be; (5/11) * (4/10) * (3/9) * (2/8) = 1/66 Simpler..using your calculator (required outcome/total possible outcomes) 5(combination function on calculator)4 / 11(combination function on calculator) 4 =1/66 I hope this was helpful