For each of the following, calculate the number of grams of Ca3(PO4)2 that could be produced, given the following equation:
3CaCO3 + 2H3PO4 ---> Ca3(PO4)2 + 3CO2 + 3H2O
a. from 12.5g of CaCO3 and 17.3g H3PO4
b. from 1.85 moles of CaCO3 and 325g of H3PO4
c. from 0.275g of CaCo3 and ).425 g of H3PO4
can you please show me on how you get it?