Is there something on the righthand side of the equals sign in the second equation? I would put each equation into y = mx+b form, for the first one, this would be:(6/5)*y = 1 - (2/3)x, ory = -(5/9)x + 1and then use your methods of graphing lines to graph both lines, and then look on your graph where they intersect. The intersection point (x,y) will be the values of x and y that make both equations true.Without knowing what's on the right hand side of the second equation, you can tell that the slope is going to be the same (-5/9), so you're answer will either be all the points on the entire line, if they're equal equations, or no solution if they're parallel, because they will never intersect.
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