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what is (3x)^5 * 2x^-2

shelly15

by shelly15 at February 09, 2012

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(3x)^5 × 2x^-2. bring the negative exponents to the denominator. ((3x)^5 × 2)/x^2. ((3^5)(x^5)(2))/x^2 (243(x^5)2)/x^2 (486(x^5))/x^2 486x^3 

88ivory 88ivory February 10, 2012

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