3^x+1/2  

⚑ Flag

f(x) = 3^x+1/2 taking natural log to both sides ln f(x) = ln 3^x+1/2 ln f(x) = x+1/2 ln3 differntiating with respect to 'x' 1/f(x)*f'(x) = (1)(ln3) f'(x) = f(x) ln3 f'(x) = 3^x+1/2 ln3 (required derivative)