Write the expression as a complex number in stanard form. 4i(3-i)(-2+8i)

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Oops, I made mistakes.  Look at this one instead:CORRECTED ANSWER:It really looks like this: (4i)(3 - i)(-2 + 8i)Step 1: Multiply the first 2 groups(12i - 4i^2)(-2 + 8i)Step 2: Realize that... i^2 = -1Step 3: Substitute [-1] for i^2(12i - 4[-1])(-2 + 8i)Step 4: Simplify the first group(12i + 4)(-2 + 8i)Step 5: Multiply again-24i + 96i^2 - 8 + 32iStep 6: Remember to substitute that i^2 = -1-24i + 96(-1) - 8 + 32iStep 7: Simplify...-24i - 96 - 8 + 32iStep 8: Put in Standard form (numbers first then 'i')-104 + 8i (answer)