Individuals carrying at least one recessive allele compromise 51% of the population. What is the percentage of all three possible genotypes? (AA,Aa,aa)

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Possible genotypes; aa, Aa, AA   If 51% of population have atleast one recessive allele then; aa+Aa = 51%= 0.51 This means that-                                                 AA (p squared) = 1.0-0.51                                                                                                = 0.49                                                                             (so p squared = 0.49) If p squared = 0.49                 p = 0.7            p +q = 1.0            So q = 0.3    q squared = 0.09   Percenatges are; AA (p squared) = 0.49 x 100 = 49%                          Aa (2PQ)         = (2x0.7x0.3) x100 = 42%                          aa (q squared) = 0.09 x 100 =9%