1)Find two consecutive even integers such that seven times the first equals six times the second 2) Find two consecutive odd numbers whos sum is 80

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2n will give you a even number for any n= a whole number other than zero. 2n + 2 is the next larger even number 7*2n = 14n 6*(2n + 2) = 12n + 12 14n = 12n +12 2n = 12 n = 6 Our desired numbers are 12 and 14 check:  7*12 = 84 and 6*14 = 84.  Yep!   Part 2:  2n-1 guarantees you an odd number for any nonzero whole number n. 2n-1  + (2n-1) +2 = 80 4n -2 + 2 = 80 4n = 80 n = 20 2n-1 = 40-1 = 39 and the next number is 41 Check: 39 + 41 = 80        Yep!