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2x2+7x-13

nicoledukes

by nicoledukes at November 15, 2011

In this problem we are finding the zeros using the Quadratic Formula.

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Original equation: 2x2 + 7x - 13 = 0 Identify coefficient values for use in quadratic formula: a = 2; b = 7; c = -13 Plug coefficient values into quadratic formula: x = (-b +/- sqrt(b2 - 4ac))/2a = (-7 +/- sqrt(72 - 4(2)(-13)))/2(2) Solve for x: x = (-7 +/- sqrt(49 + 104))/4x = (-7 +/- sqrt(153))/4 x = (-7 + 12.4)/4 = 5.4/4 = 1.35   ORx = (-7 - 12.4)/4 = -19.4/4 = -4.85         

karrjg karrjg November 17, 2011

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