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But surely x^2 +36=0 so (x+6)(x-6)=0 so x=6 or x=-6
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by whelanbt11 at October 17, 2011

It seems the video is wrong.

solving quadratic equations using square roots

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x^2 +36 is simply an upward opening parabola that is shifted vertically upward 36 units. The vertex shifts from (0,0) to (0,36) This parabola has no real solutions only two imaginary solutions.

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Steve204 October 17, 2011

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in addition to what steve said there can be no real solutions because if x^2 + 36=0 then x^2= -36 and a squared can not equal a real number

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juliao. October 17, 2011

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But surely x^2 +36=0 so (x+6)(x-6)=0 so x=6 or x=-6 ⚑ Flag

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But surely x^2 +36=0 so (x+6)(x-6)=0 so x=6 or x=-6
⚑ Flag