I substitute w=x+3 -> x=w-3 and dw=dx ∫wdw/(3-w-3)^(2/3) = ∫wdw/(-w)^(2/3) = ∫ -w . w^(-2/3) dw = ∫ - w^1/3 dw = (- w ^(4/3))/ 4/3 + c =( -3w ^(4/3) )/4 + c = (-3(x+3)^4/3)/4 +c. The answer is different from you. What have I done wrong? Pls check my solution. Thanks. Joy

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by joyleap at October 12, 2011