your not solving this problem correctly these are 2 radicals Radical x+2 + radical 3x+7 =1

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Original Equation: (x + 2)^1/2 + (3x + 7)^1/2 = 1 Isolate one radical on the left side by subtracting the other radical from both sides of the equation: (3x + 7)^1/2 = 1 - (x + 2)^1/2 Square both sides of the equation to get rid of radical on the left side: 3x + 7 = 1 - 2(x + 2)^1/2 + x + 2 Isolate radical on right side by subtracting (1 + x + 2) from both sides: 3x + 7 - (1 + x + 2) = -2(x + 2)^1/2 Combine like terms on left si 2x + 4 = -2(x + 2)^1/2 Square both sides of the equation to get rid of radical on right side: 4x² + 16x + 16 = 4(x + 2) Distribute right side: 4x² + 16x + 16 = 4x + 8 Set right side to zero: 4x² + 16x + 16 - 4x - 8 = 0 Combine like terms on left side: 4x² + 12x + 8 = 0 Divide both sides by 4: x² + 3x + 2 = 0 Factor left side: (x + 2)(x + 1) = 0 Set each factor to zero and solve for x in each case: x + 2 =   0;  x + 1 =  0      x = -2;        x = -1