Two cars A and B start from a given point and travel on a straight road at average speeds of 70 km/h and 90 km/h respectively. If B starts 1 h after A find out how long before A traveled before B overtook it and the distance each traveled before they met.

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tony - B starts 1 hour ahead, so that equals 70 km ahead, agree? (70 km/h x 1h = 70 km) So, the distance between B an A, when A starts is 70 km. A is catching up to B at 20 km/h, right? (90 - 70 = 20) So, it takes 70/20 or 3.5h for A to catch up to B. Where do they meet? I'll leave that math for you! Hope that helps!