if 2 is the exponent of mn as in (mn)^2, the answer is m^5n^3. To get to this answer, just remember that the 2 exponent is distributed to both the m and the n. Then, you just add the exponents of common bases: the exponents of m are 3 and 2, and those of n are 1 and 2.If you really meant the 2 was the exponent of the n, as in mn^2, then the answer would be m^4n^3, and the solution is obtained the same way, only that in this case the 2 exponent isn't distributed.
