find the exact value of the expressioncos(theta) = 21/29 (theta) lies in quadrant IV find sin 2 (theta)

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Octavia -First, ALWAYS draw the triangle!  In this problem the triangle is in quadrant IV, so draw it and label it like this:Now, since this is right triangle, use Pythagorean to solve for the missing leg.  You should get -20.  It is negative, because in quadrant IV the y-axis is negative, agree?Now use this formula for sin(2θ):sin(2θ) = 2sin(θ)cos(θ)You already know what cos(θ) equals.  It is 21/29.  From the graph above, sin(θ) = -20/29.Now, you have everything you need to solve the problem. I'll leave the math for you.Hope that helps