i need hw help with precalc btw *=degrees  1. A ship leaves port at 11 am traveling at 20 knots and bearing S40*W How many nautical miles west of the port will the ship be at 5 pm

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Dave -Here is help with #1.  ALWAYS sketch a picture to get a good idea what the problem is asking.  Here is a sketch:If the ship leaves port at point C and travels for 6 hours at 20 knots per hr, then it traveled 6 * 20 = 120 knots. In the sketch above, the distance from C to A is 120 knots.If the ships bearing is S40*W, then the angle between the line segment CA and the y-axis is 40* which means angle BCA is 50*, agree?The question asks how far west of port.  That is simply the length of segment CB. Since this is a right triangle, you can use cos(50*) = CB/120.  Look at the sketch and convince yourself that is correct. (Remember, cosine equals adjacent over hypotenuse).Just solve for the length of segment CB and you will have your answer.Same with Prob. #2.  Sketch the picture, use right triangle properties to solve.Hope that helps