write the equation represented in the table below: x      36      39      48      60 y       4        5        8       12  

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First, take any to pairs for the table, I'm going to use (36,4) and (60,12)Using those points I can find a slope with (Y2-Y1)\(X2-X1) or (12-4)/(60-36) which gives us 8/24 or 1/3Now we have an "m" to put into y=mx+b, let's use one of our unused co-ordinates to find "b", I'll take (48,8)     8=((1/3)*48)+b=>8=16+b=>-8=bSo, to sum up, m=(1/3) b= -8 and to verify, we have ne unused point, how convenientDoes ((1/3)*39)-8=5 ? =>(1/3)*39=5+8=>13=13good times..