Hi Melenie131,
To solve this problem, we need to set up an equation. First, we set our our equals value ( in this case the sum of the integers which is -66) Now, we can set some variables. We can use the information givin to do this.We know there are three consecutive intergers adding up to -66. (These intergers are most likley negative). Lets call the first of the three intergers X. We proceed by adding the second interger, which we can label X-1. (This occurs by use of the rule of signs, if I had -1 and added -1 to it, the sum would be -2 I can keep going consecutivly in this manner) By this logic, we add the third interger we label as X-2. What we have done is set up an linear equation to solve this problem.
X+(X-1)+(X-2)= -66
mutiplying numbers and X's gives us:
3X-3=-66
Adding three over gives :
3X=-63
Dividing by 3 gives :
X=-21
Is this the answer? To find out, plug the X value into the original equation.
-21+(-21-1)+(-21-2)= -66
intergers are -21,-22, -23
Ben