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calculate the energy required to change 1 mole of ice at -10 degree celseuis to water at 15 degrees celseuis.

Tony335

by Tony335 at May 30, 2011

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C = 4.18 J/g*degH of fusion = 334 J/g1 mole of ice = 18 gq=m*C*deltaTq=18g * 4.18 J/g*deg * 25 deg (+ H of fusion)q = 1881 J + (6012 J) = 7893 J

Seth_Warncke Seth_Warncke June 07, 2011

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